Dojo ajax return and a for command

Submitted by timgerr on Fri, 12/14/2007 - 20:19.

Dojo Core Support

Hey all, I hope all are doing well. I have a goody question for ya, it isnt really a dojo question but I think I can get some help here. I have a json string:

{items:[{"id":"62","firstName":"Dd","lastName":"Dd","title":"Kljasdfsdf","userphone":"222 333 4444","phoneext":"33","degreeyear":"1900","yrscompany":"0","companyname":"44","addressone":"adsf","addresstwo":"22","state":"CT","zip":"12345","country":"Anguilla","num_eng":"0","mech_eng":"0","mech_eng_yrs_exp":"0","elec_eng":"0","elec_eng_yrs_exp":"0","soft_eng":"0","soft_eng_yrs_exp":"0","sys_eng":"0","sys_eng_yrs_exp":"0","naics_code":"0","creation":"20071213","modified":"20071214-11:43:55","serial":"4436578972312394071312"}]}

And I have an ajax request that looks like this:

function addEvent() {
	var URL = new Object();
	URL.address = 'http://miys02ae211935l/testingOnly/test.json';
	var eventsubmit = ({
    	url: URL.address,
        content: {'p1':'WTF'},
		handleAs: "json",
        timeout:5000,
        handle: function(response, ioArgs){            
        	return response;
        }
	});
	var def = dojo.xhrPost(eventsubmit);
	def.addCallback('doMe');
}

function doMe(data, ioArgs)
{
	console.debug(data.items[0].id);
	for(var i in data.items[0]){
		console.debug(i);
		console.debug(data.items[0].i);
	}
}

So when I do console.debug(i); I get this,

id
firstName
lastname
.......

but when I do console.debug(data.items[0].i); I get

undefined
undefined
undefined
.......

How can I spit out what is in the object?

Thanks,
timgerr

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Depending on what data you

Submitted by frankf on Fri, 12/14/2007 - 23:34.

Depending on what data you want to see and how you want it presented, you could:

for(var i=0;i

for(var i=0;i

With the for command/*

Submitted by timgerr on Sat, 12/15/2007 - 06:07.

With the for command

for(var i in data.items[0]){
                console.debug(i);
                console.debug(data.items[0].i);
        }

when I do the console.debug(i) I get the

id
firstName
lastname

I dont want to have to explicitly give all the

data.items[0].id
data.items[0].firstname
data.items[0].lastname

I want to do loop through data.items[0].i because i has all I need. Can this be done?

Thanks,
timgerr

Try this...

Submitted by frankf on Sat, 12/15/2007 - 21:12.

var value;
for(var i in data.items[0]){
  value = eval("data.items[0]." + i);console.log(i + " = " + value);
}

or, better,

var value;
for(var i in data.items[0]){
  value = data.items[0][i];console.log(i + " = " + value);
}

Note: Javascript does not guarantee the order in which objects (attributes) are returned in a for(var i in...) loop. This may or may not be important in your application.

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